5x-3[x+1]=2[x+3]-5

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Solution for 5x-3[x+1]=2[x+3]-5 equation:


Simplifying
5x + -3[x + 1] = 2[x + 3] + -5

Reorder the terms:
5x + -3[1 + x] = 2[x + 3] + -5
5x + [1 * -3 + x * -3] = 2[x + 3] + -5
5x + [-3 + -3x] = 2[x + 3] + -5

Reorder the terms:
-3 + 5x + -3x = 2[x + 3] + -5

Combine like terms: 5x + -3x = 2x
-3 + 2x = 2[x + 3] + -5

Reorder the terms:
-3 + 2x = 2[3 + x] + -5
-3 + 2x = [3 * 2 + x * 2] + -5
-3 + 2x = [6 + 2x] + -5

Reorder the terms:
-3 + 2x = 6 + -5 + 2x

Combine like terms: 6 + -5 = 1
-3 + 2x = 1 + 2x

Add '-2x' to each side of the equation.
-3 + 2x + -2x = 1 + 2x + -2x

Combine like terms: 2x + -2x = 0
-3 + 0 = 1 + 2x + -2x
-3 = 1 + 2x + -2x

Combine like terms: 2x + -2x = 0
-3 = 1 + 0
-3 = 1

Solving
-3 = 1

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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